(x^2)-8x+41=0

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Solution for (x^2)-8x+41=0 equation:


Simplifying
(x2) + -8x + 41 = 0
x2 + -8x + 41 = 0

Reorder the terms:
41 + -8x + x2 = 0

Solving
41 + -8x + x2 = 0

Solving for variable 'x'.

Begin completing the square.

Move the constant term to the right:

Add '-41' to each side of the equation.
41 + -8x + -41 + x2 = 0 + -41

Reorder the terms:
41 + -41 + -8x + x2 = 0 + -41

Combine like terms: 41 + -41 = 0
0 + -8x + x2 = 0 + -41
-8x + x2 = 0 + -41

Combine like terms: 0 + -41 = -41
-8x + x2 = -41

The x term is -8x.  Take half its coefficient (-4).
Square it (16) and add it to both sides.

Add '16' to each side of the equation.
-8x + 16 + x2 = -41 + 16

Reorder the terms:
16 + -8x + x2 = -41 + 16

Combine like terms: -41 + 16 = -25
16 + -8x + x2 = -25

Factor a perfect square on the left side:
(x + -4)(x + -4) = -25

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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